Created Condition statemenet (markdown)

Condition-statemenet.md

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+SMNP language has support for good old condition statement 
+and its syntax is inspired by Java language.
+
+# `if` statement
+The simplest form consists only of `if` keyword followed 
+by condition bounded on both sides with
+parentheses (`(` and `)`) and statement 
+(or block of code):
+```
+if (2 > 3) println("It gonna never be displayed!");
+
+# or (using block of code)
+
+if (2 > 3) {
+    println("It gonna never be displayed!");
+}
+```
+
+Just like in Java condition **must be** of `bool` type. 
+```
+# Correct examples
+if (true) println();
+if (false) println();
+if (not false) println();
+if (0 == 0) println();
+if ("hello".length > 0) println();
+if (true and not true or not false and true) println();
+if (true and (not true or not false) and true) println();
+
+# Incorrect examples
+if () println();
+if (0) println();
+if (1) println();
+if ("hello") println();
+if (true.toString()) println();
+```
+
+# `if-else` statement
+You can use additional `else` clause which is always executed
+when condition is resolved to `false`.
+
+Example:
+```
+if (2 > 3) println("It gonna never be displayed!");
+else println("but this always will be displayed");
+
+# or you can use blocks of code to increase readability
+
+if (2 > 3) {
+    println("It gonna never be displayed!");
+} else {
+    println("but this always will be displayed");
+}
+```
+
+Remember that only one condition statement branch (`if` or `else`) 
+can be executed in single statement. There is no possibility 
+to execute both clauses:
+```
+x = 1;
+
+if (x > 0) {
+    println(true);
+} else {
+    println(false);
+}
+
+if (x < 0) {
+    println(false);
+} else {
+    println(true);
+}
+``` 
+Above example will print `true` twice. First statement's condition is met, 
+so `if` clause did execute, but second statement's condition is resolved
+to false so `else` clause did execute.
+
+# `if-else-if-else-if-...` statement
+Above constructions are sufficient 
+to create `if-else-if-...` pseudo-construction.
+Thanks to it, you are able to put additional execution branches
+to existing condition statement.
+_Pseudo_ in this case means that there is no special parsing rules 
+nor evaluators related to this construction. It is just a combination 
+of `if` and `if-else` statements presented above.
+
+Example:
+```
+x = 3;
+if (x == 0) {
+    println("x is zero");
+} else if (x == 1) {
+    println("x is one");
+} else if (x == 2) {
+    println("x is two");
+} else if (x == 3) {
+    println("x is three");
+} else {
+    println("x is neither zero, one, two nor three");
+}
+
+# its technically equivalent of
+
+if (x == 0) {
+    println("x is zero");
+} else { 
+    if (x == 1) {
+        println("x is one");
+    } else {
+        if (x == 2) {
+            println("x is two");
+        } else {
+            if (x == 3) {
+                println("x is three");
+            } else {
+                println("x is neither zero, one, two nor three");
+            }
+        }
+    }
+}
+```
+Thanks to its tree-like construction control flow falls through all conditions.
+A branch first matched branch is executed 
+and following conditions are not checked anymore:
+```
+x = 0
+if (x == 1) {
+    println();           # Condition is resolved to false
+} else if (x == 0) {
+    println();          # Condition is met
+} else if (x == 0) {
+    println();           # Condition is also met, 
+}                       # but it hasn't been even checked because above
+                        # branch has been already matched and executed
+```
+
+# Lazy evaluation
+It's also good place to mention, that both `and` and `or` operators support lazy evaluation of their operands.
+
+It means that:
+* in case of `A and B` expression, `B` expression will be evaluated only when `A` expression is evaluated to `true`
+* in case of `A or B` expression, `B` expression will be evaluated only when `A` expression is evaluated to `false`.
+
+It allows you for example to keep availability-check with actual condition togheter, for example:
+```
+function test(x: string) {
+  # You are allowed to use following if-statement:
+  if(x.length >= 5 and x.charAt(4) == "o") {
+     println(x);
+  }
+}
+
+# Now, let's check:
+test("Hello");
+
+# In this case x.length == 5 so the second operand 
+# will be evaluated to true and the "Hello" message will be displayed.
+
+# However, in the following case:
+test("abc");
+
+# x.length < 5 and so we don't need to evaluate 
+# the second operand to know the value of condition.
+# Thanks to that, there is no risk to end up 
+# with error, that we're trying to get not existing character of string
+```